Year 10 · Unit 10.2

10.2 Exponents and Indices

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Quizzes

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Revision notes

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The big idea. Why keep an answer exact when a calculator gives a decimal? Index laws, negative and fractional indices, exponential equations, surds and rationalising denominators.

Key vocabulary
WordMeaning
Index (power, exponent)the small number that says how many times to multiply the base, e.g. the 3 in 2³
Basethe number that is being multiplied by itself, e.g. the 2 in 2³
Negative indexan index that gives a reciprocal: 2⁻³ = 1/2³ = 1/8
Fractional indexan index that means a root: 8^(1/3) is the cube root of 8
Reciprocal1 divided by a number: the reciprocal of 8 is 1/8
Exponential equationan equation with the unknown in the index, e.g. 2^x = 32
Rational numbera number that can be written as a fraction of two integers
Irrational numbera number that cannot be written as a fraction, e.g. √2
Surdan irrational root left in exact form, such as √2 or √12
Like surdssurds with the same root part, e.g. 3√2 and 5√2, which can be added or subtracted
Numeratorthe number or expression above the line in a fraction
Denominatorthe number or expression below the line in a fraction
Rationalise the denominatorrewrite a fraction so that the denominator has no surd
Conjugatethe same two terms with the opposite sign between them: the conjugate of 3 + √2 is 3 − √2
Index laws (positive and zero indices)
  • am × an = am+n (same base: add the powers). am ÷ an = am−n.
  • (am)n = amn. (ab)n = anbn.
  • a⁰ = 1 because an ÷ an = a0 = 1.
  • Expand to see why: x³ × x² = (x·x·x)(x·x) = x⁵.
  • The laws need the same base: 2³ × 3² cannot be combined.
Negative and fractional indices
  • a−n = 1 ÷ an: a negative index is a reciprocal. 2−3 = 1/8.
  • (a/b)−n = (b/a)n: flip, then use the positive power.
  • a1/n = ⁿ√a. 91/2 = 3, 271/3 = 3.
  • am/n = (ⁿ√a)m. 82/3 = (³√8)² = 4.
  • The pattern 2³ = 8, 2² = 4, 2¹ = 2, 2⁰ = 1, 2−1 = 1/2 shows why.
Exponential equations
  • If ax = ay (same base, a > 0, a ≠ 1) then x = y.
  • Write both sides with the same base: 2x = 32 = 2⁵, so x = 5. 9x = 27 gives 32x = 3³ and x = 3/2.
  • Answers can be negative or fractional: 2x = 1/8 = 2−3 gives x = −3.
  • With an algebraic exponent: 4x+1 = 2x+7 → 22x+2 = 2x+7 → 2x + 2 = x + 7 → x = 5. Check by substituting.
  • The rule fails for base 1 and 0.
Surds
  • A surd is an irrational root left exact, such as √2 or √12.
  • Simplify using the largest square factor: √12 = √4 × √3 = 2√3. √50 = 5√2.
  • Add/subtract like surds only: 3√2 + 5√2 = 8√2. √2 + √3 stays as it is.
  • Multiply: √a × √b = √(ab), and √a × √a = a. 2√3 × 3√2 = 6√6.
  • Expand brackets as normal: √2(3 + √2) = 3√2 + 2. (1 + √3)² = 1 + 2√3 + 3 = 4 + 2√3.
Rationalising the denominator
  • Rationalise = remove the surd from the denominator, because a rational denominator is easier to use and compare.
  • Single surd: 1/√2 = (1 × √2)/(√2 × √2) = √2/2. Multiplying by √2/√2 is multiplying by 1, so the value is unchanged.
  • Conjugate: the same terms with the opposite sign. The conjugate of 3 + √2 is 3 − √2.
  • 1/(3 + √2) = (3 − √2)/((3 + √2)(3 − √2)) = (3 − √2)/(9 − 2) = (3 − √2)/7.
  • The product of a number and its conjugate is rational: (a + √b)(a − √b) = a² − b.
Sequences with surd terms
  • Simplify every surd term first: √2, √8, √18 = √2, 2√2, 3√2.
  • That is an arithmetic sequence with d = √2.
  • Geometric check: √2, 2, 2√2 has r = √2 (2 ÷ √2 = √2, and 2√2 ÷ 2 = √2).
  • Write un in exact form: un = √2 × n for the first sequence.
Common mistakes
  • ✕ “x³ × x² = x⁶.” ✓ Add the powers: x⁵.
  • ✕ “2−3 = −8.” ✓ A negative index gives a reciprocal: 1/8.
  • ✕ “81/3 = 8/3.” ✓ A power of 1/3 is a cube root: 2.
  • ✕ “√2 + √3 = √5.” ✓ Unlike surds cannot be added: √2 + √3 stays as it is.
  • ✕ “(a + b)2 = a² + b².” ✓ Expand: a² + 2ab + b². So (1 + √3)² = 4 + 2√3.

Practice booklet

Unit 10.2 Practice Booklet
mathscafe.net
Lorna Brown © 2026
Ms B’s mathscafe

Practice Booklet

MYP 4 · Year 10 Mathematics (Extended)
Unit 10.2 · Exponents and Indices
Name:
10.2.1
Index laws · Questions 1–20
10.2.1b
Negative and fractional indices · Questions 21–38
10.2.2
Comparing exponents · Questions 39–57
10.2.3
Algebraic exponents · Questions 58–76
10.2.4 (a)
Surds: what they are and simplifying · Questions 77–95
10.2.4 (b)
Multiplying and collecting surds · Questions 96–114
10.2.4b
Rationalising the denominator · Questions 115–132
10.2.5
Sequences with surds · Questions 133–151
Homework
Homework page and checking record
Answers
For checking and correcting in green pen
MYP 4 · Year 10 · Unit 10.2 Exponents and Indices · Practice BookletMs B’s mathscafe · page 1

How to use this booklet and your homework

Read this first

Choosing your level

Every part of the unit has four levels. Start where you feel comfortable and move between them freely. Most questions ask you to explain as well as answer, because being able to say why is what makes a method stick.

Learning

The standard case with small numbers, with the method set out for you.

Practising

The method on its own, with your reasoning written out.

Challenging

Harder, with several steps, and finding what is wrong with someone else's working.

Mastery

Explaining why a rule must be true, and testing it on new cases.

Working on your homework

Pens and setting out

  • Answers in blue or black non-erasable pen, or in pencil.
  • Colour and highlighters are for annotating your work and showing the steps of a method.
  • Never erase a mistake. Rework it underneath so you can see what changed.
Green pen is for checking. When you finish, use the answers at the back to check your work.
  • Got it wrong? Circle the question number, then make your correction and write your error analysis in green pen.
  • Still can’t work out how to solve it? Put a star ★ next to the question number, so we know to go over it in class.

Each sheet

  • Your name goes on every sheet, because they are handed in one at a time.
  • Each question is worth up to 3 marks. If a question has parts (a, b, c…), each part is marked out of 3. At the end of each level, write your score out of the total for that level.
  • Questions are numbered 1, 2, 3… all the way through the booklet, so we can say exactly which ones to do.
  • If you are stuck after trying, ask for help. Showing me what you tried is a good start.
MYP 4 · Year 10 · Unit 10.2 Exponents and Indices · Practice Bookletmathscafe.net
Lorna Brown © 2026
page 2

10.2.1 Index laws

Learning · Practising
Name:

Key vocabulary

WordMeaningExample
basethe number being multiplied by itself2 in 23
indexhow many times the base is used as a factor3 in 23
powera base with an index23 = 8
same basethe same number or letter52 and 54

Laws (same base only): am × an = am+n · am ÷ an = am−n · (am)n = amn · a0 = 1

Learning

1
Write 2 × 2 × 2 × 2 as a power
2
a) Write 23 × 22 in full, with every 2 showing b) Count the 2s and write the answer as one power of 2
3
Write 34 × 35 as a single power of 3
4
Write 78 ÷ 73 as a single power of 7
5
Write (52)3 in full, then as a single power of 5
6
Work out a) 90 b) 1000 c) 10
Learning score / 27

Practising

7
Simplify a) x4 × x3 b) y9 ÷ y2 c) (a3)5
8
Simplify (2x3)4
9
Simplify 12x53x2
10
Simplify 3a2b × 4ab3
11
Simplify (3a2b)3
Practising score / 21
Parent / guardian signature:
MYP 4 · Year 10 · Unit 10.2 Exponents and Indices · Practice Bookletmathscafe.net
Lorna Brown © 2026
page 3

10.2.1 Index laws

Challenging · Mastery
Name:

Challenging

12
Simplify (2x3)2 × 3x46x5
13
Work out 40 + (3x)0 + 5x0, where x is not zero
14
Find n: a) 3n ÷ 34 = 36 b) (5n)2 = 512
15
Find and describe the mistake. Sam writes 23 × 32 = 65
16
Write 23 × 23 × 23 as a power of 2 in two different ways
Challenging score / 18

Mastery

17
Use the divide law on 53 ÷ 53 to explain why 50 = 1
18
Explain why 34 × 32 = 36, but 34 + 32 is not 36. Work out both sides to check
19
Show that (23)4 = (24)3, then explain why (am)n = (an)m
20
A square has side 25 cm. Write its area as a power of 2 and work it out
Mastery score / 12
Parent / guardian signature:
MYP 4 · Year 10 · Unit 10.2 Exponents and Indices · Practice Bookletmathscafe.net
Lorna Brown © 2026
page 4

10.2.1b Negative and fractional indices

Learning · Practising
Name:

Key vocabulary

WordMeaningExample
reciprocala fraction turned upside downthe reciprocal of 4 is 14
negative indexmeans take the reciprocala−n = 1an
fractional indexmeans a root; the denominator is the rootamn = (n-th root of a)m
rootundoes a powerthe cube root of 8 is 2

Do the root first, then the power.

Learning

21
Continue the pattern. 23 = 8, 22 = 4, 21 = 2, 20 = 1, 2−1 = ___, 2−2 = ___
22
Write as a fraction a) 2−3 b) 10−2 c) 5−1
23
Work out a) 2512 b) 10012 c) 813 d) 2713
24
Write the reciprocal of a) 4 b) 23
Learning score / 30

Practising

25
Evaluate a) 3−2 b) 4−3 c) 10−4
26
Evaluate a) (12)−4 b) (23)−2
27
Evaluate a) 1614 b) 3215 c) 100013
28
Evaluate a) 823 b) 2723 c) 432
29
Write 3−2 × 35 as a single power of 3, then evaluate it
Practising score / 36
Parent / guardian signature:
MYP 4 · Year 10 · Unit 10.2 Exponents and Indices · Practice Bookletmathscafe.net
Lorna Brown © 2026
page 5

10.2.1b Negative and fractional indices

Challenging · Mastery
Name:

Challenging

30
Evaluate a) 9−12 b) 27−23 c) 16−34
31
Evaluate (49)−32
32
Simplify x−2 × x5 ÷ x−1
33
Find and describe the mistake. Jo says 2−3 = −8
34
a) Write 132 as a power of 2 b) Write 8 × 2−5 as a single power of 2, then as a fraction
Challenging score / 24

Mastery

35
Use a12 × a12 to explain why a12 must be the square root of a
36
A student says 432 = 6 because 4 × 3 ÷ 2 = 6. Explain the mistake and give the correct value
37
Evaluate 8−23, saying which rule you use at each step
38
Put in order, smallest first, without a calculator: 2−1, 412, 80, 27−13
Mastery score / 12
Parent / guardian signature:
MYP 4 · Year 10 · Unit 10.2 Exponents and Indices · Practice Bookletmathscafe.net
Lorna Brown © 2026
page 6

10.2.2 Comparing exponents

Learning · Practising
Name:

Key vocabulary

WordMeaningExample
common basethe same base on both sides4 and 8 are both powers of 2
equatemake two things equal2x = 25, so x = 5

Steps: 1 choose a common base. 2 rewrite each side as a power of it. 3 equate the exponents. 4 solve and check.

Learning

39
Solve 2x = 8
40
Solve a) 5x = 25 b) 3x = 81 c) 10x = 1000
41
Write as a power of 2 a) 4 b) 16 c) 32
42
Solve 2x = 64 by writing 64 as a power of 2
43
Solve 5x = 1
Learning score / 27

Practising

44
Solve a) 2x = 256 b) 5x = 625 c) 10x = 1 000 000
45
Solve 25x = 125
46
Solve 4x = 116
47
Solve 8x = 16
48
Solve 9x = 27
Practising score / 21
Parent / guardian signature:
MYP 4 · Year 10 · Unit 10.2 Exponents and Indices · Practice Bookletmathscafe.net
Lorna Brown © 2026
page 7

10.2.2 Comparing exponents

Challenging · Mastery
Name:

Challenging

49
Solve a) 27x = 9 b) 3x = 181 c) 8x = 14
50
Solve 4x = 32
51
Solve (12)x = 8
52
Find and describe the mistake. Dee solves 9x = 27. She writes 3x = 33, so x = 3
53
Solve 2x = 0.25
Challenging score / 21

Mastery

54
Explain why 3x = 5 cannot be solved by writing both sides as a power of 3. Between which two whole numbers is x?
55
Explain why 1x = 1 has many solutions, so we cannot compare exponents when the base is 1
56
a) A culture of bacteria starts with 1 cell and doubles every hour. After how many hours are there 1024 cells? b) Another culture triples every hour. After how many hours does it reach 729 cells?
57
Solve 16x = 8 and 8y = 16. Show that x × y = 1 and explain why
Mastery score / 15
Parent / guardian signature:
MYP 4 · Year 10 · Unit 10.2 Exponents and Indices · Practice Bookletmathscafe.net
Lorna Brown © 2026
page 8

10.2.3 Algebraic exponents

Learning · Practising
Name:

Key vocabulary and steps

WordMeaning
exponentthe power; here it contains x
common basewrite both sides as powers of the same base
equatemake the exponents equal, then solve

Steps: 1 match the bases. 2 use the index laws on the exponents. 3 equate the exponents and solve. 4 check by substitution.

Learning

58
Write 8 as a power of 2
59
Simplify a) 23 × 24 b) (23)2
60
Write as a power of 2 a) 4x b) 8x c) 16x
61
Solve 2x+1 = 25
62
Solve 32x = 38
Learning score / 24

Practising

63
Solve 9x = 3x+4
64
Solve 5x+1 = 25x
65
Solve 2x−1 = 4x+1
66
Solve 32x+1 = 27x−1
67
Solve 5x+2 = 25x−3
Practising score / 15
Parent / guardian signature:
MYP 4 · Year 10 · Unit 10.2 Exponents and Indices · Practice Bookletmathscafe.net
Lorna Brown © 2026
page 9

10.2.3 Algebraic exponents

Challenging · Mastery
Name:

Challenging

68
Solve 23x−1 = 4x+2
69
Solve 4x+1 = 8x
70
Solve (12)x = 4x+3
71
Find and describe the mistake. Ali solves 4x+1 = 2x+5. He writes 4x+1 = 22x+1
72
Check by substitution that x = 3 is a solution of 4x+1 = 2x+5
Challenging score / 15

Mastery

73
Solve 2x × 4x+1 = 128
74
Explain why 27x−1 = 33x−3 and not 33x−1
75
a) A population is 5 × 2t after t hours. When is it 160? b) When is 5 × 2t equal to 5 × 4t−2?
76
Write an equation of the form 3ax+b = 9cx+d whose solution is x = 2. Show that it works
Mastery score / 15
Parent / guardian signature:
MYP 4 · Year 10 · Unit 10.2 Exponents and Indices · Practice Bookletmathscafe.net
Lorna Brown © 2026
page 10

10.2.4 (a) Surds: what they are and simplifying

Learning · Practising
Name:

Key vocabulary

WordMeaningExample
surda root that cannot be written exactly as a whole number or fraction√7
irrationala number whose decimal never ends or repeats√2
perfect squarea whole number squared1, 4, 9, 16, 25, 36, 49
highest perfect square factorthe largest square that divides the numberfor 72 it is 36
simplest formthe number under the root has no square factor6√2

Rule: √ab = √a × √b. Pull out the highest perfect square factor.

Learning

77
List the first ten perfect squares
78
Which of these are surds? √16 √7 √25 √10
79
Complete: √18 = √9 × √2 = ___ √2
80
Simplify √8 by writing it as √4 × √2
81
Simplify √12. Hint: which perfect square goes into 12?
Learning score / 15

Practising

82
Simplify √48
83
Simplify √75
84
Simplify √72, using the highest perfect square factor
85
Simplify √45
86
Simplify 5√8
Practising score / 15
Parent / guardian signature:
MYP 4 · Year 10 · Unit 10.2 Exponents and Indices · Practice Bookletmathscafe.net
Lorna Brown © 2026
page 11

10.2.4 (a) Surds: what they are and simplifying

Challenging · Mastery
Name:

Challenging

87
Simplify a) √180 b) 3√50 c) √200
88
Write 6√2 as a single surd √n
89
Find and describe the mistake. A student writes √9 + √16 = √25 = 5
90
Simplify √98 and √32
91
Simplify √755
Challenging score / 21

Mastery

92
A student simplifies √72 as 2√18. Is the value right? Is it in simplest form? Explain
93
Show that √8 and √18 are both whole-number multiples of √2
94
Explain why √2 cannot be written exactly as a fraction or a finite decimal
95
A square has area 50 cm2. Find the exact side length in simplest form
Mastery score / 12
Parent / guardian signature:
MYP 4 · Year 10 · Unit 10.2 Exponents and Indices · Practice Bookletmathscafe.net
Lorna Brown © 2026
page 12

10.2.4 (b) Multiplying and collecting surds

Learning · Practising
Name:

Key vocabulary

WordMeaningExample
like surdssurds with the same number under the root3√2 and 5√2
unlike surdsdifferent numbers under the root, so they cannot be collected√2 and √3

Rules: √a × √b = √ab · √a × √a = a · collect like surds · expand with the box method, then simplify

Learning

96
Work out √2 × √3
97
Work out √5 × √5
98
Work out 3√2 × 2√5
99
Simplify 4√3 + 2√3
100
Simplify 7√5 − 3√5
Learning score / 15

Practising

101
Simplify 3√2 × 4√6
102
Expand √3(5 − √3)
103
Expand (3 + √2)(1 + √2)
104
Simplify √48 − √12
105
Simplify √8 + √50
Practising score / 15
Parent / guardian signature:
MYP 4 · Year 10 · Unit 10.2 Exponents and Indices · Practice Bookletmathscafe.net
Lorna Brown © 2026
page 13

10.2.4 (b) Multiplying and collecting surds

Challenging · Mastery
Name:

Challenging

106
Expand (3 + √2)2
107
Expand (4 + √3)(4 − √3)
108
Expand (√5 + 2)(√5 − 2)
109
Find and describe the mistake. Tom writes (3 + √2)2 = 9 + 2 = 11
110
Simplify √45 + √20 − √5
Challenging score / 15

Mastery

111
A student writes √3 + √2 = √5. Use a calculator to show this is wrong, and explain why
112
Find the exact area of a square with side (2 + √3) cm
113
A right-angled triangle has shorter sides 2√3 cm and √6 cm. Find the hypotenuse exactly
114
Find x if √x + √4x = 3√5
Mastery score / 12
Parent / guardian signature:
MYP 4 · Year 10 · Unit 10.2 Exponents and Indices · Practice Bookletmathscafe.net
Lorna Brown © 2026
page 14

10.2.4b Rationalising the denominator

Learning · Practising
Name:

Key vocabulary

WordMeaningExample
rationaliserewrite so the denominator is a whole number1√2 = √22
conjugatesame terms, opposite sign between them3 + √2 and 3 − √2
difference of two squares(a + b)(a − b) = a2 − b2(3 + √2)(3 − √2) = 7

Multiply top and bottom by √b, or by the conjugate of the denominator.

Learning

115
Work out √7 × √7
116
Work out 1√2 × √2√2 and write the answer as a fraction
117
Rationalise a) 3√3 b) 10√5
118
Write the conjugate of a) 3 + √2 b) 4 − √5 c) √7 + 1
Learning score / 21

Practising

119
Rationalise a) 6√3 b) 4√2 c) 15√5
120
Rationalise 32√3
121
Rationalise 103√2
122
Expand (4 + √3)(4 − √3)
123
Rationalise 53 + √2
Practising score / 21
Parent / guardian signature:
MYP 4 · Year 10 · Unit 10.2 Exponents and Indices · Practice Bookletmathscafe.net
Lorna Brown © 2026
page 15

10.2.4b Rationalising the denominator

Challenging · Mastery
Name:

Challenging

124
Rationalise 1√2 + 1
125
Rationalise 23 − √5
126
Rationalise 6√7 + 1
127
Find and describe the mistake. Ben rationalises 12 + √3 by multiplying the top and bottom by 2 + √3
128
Rationalise 4√5 − 1
Challenging score / 15

Mastery

129
Explain why multiplying a fraction by its conjugate over itself does not change its value, even though it looks different
130
Rationalise √5√5 + √2
131
Simplify 12 − √3 + 12 + √3
132
A rectangle has area 6 cm2 and length (3 + √3) cm. Find the width in the form a − √b
Mastery score / 12
Parent / guardian signature:
MYP 4 · Year 10 · Unit 10.2 Exponents and Indices · Practice Bookletmathscafe.net
Lorna Brown © 2026
page 16

10.2.5 Sequences with surds

Learning · Practising
Name:

Key vocabulary

WordMeaningExample
common differenced: the gap between terms in an arithmetic sequence√3, 2√3, 3√3: d = √3
common ratior: what you multiply by each time in a geometric sequence1, √5, 5: r = √5
general termun: the rule for any termun = n√3

Arithmetic: un = u1 + (n − 1)d. Geometric: un = u1 × rn−1. Simplify every surd first.

Learning

133
Simplify a) √12 b) √27
134
Simplify √20, √45 and √80
135
Write the next term: √2, 2√2, 3√2, …
136
a) Simplify each term of √3, √12, √27 b) Find the common difference d
137
Write un for √3, 2√3, 3√3, …
Learning score / 21

Practising

138
For √8, √32, √72: simplify each term, then find d and un
139
The sequence 2, 2√3, 6, 6√3 is geometric. Find r and the next term
140
For the geometric sequence 1, √5, 5, 5√5, … find r and u6
141
The sequence √5, 3√5, 5√5, … is arithmetic. Find d, un and u10
142
Is √2, 2, 2√2, 4 arithmetic or geometric? Give d or r
Practising score / 15
Parent / guardian signature:
MYP 4 · Year 10 · Unit 10.2 Exponents and Indices · Practice Bookletmathscafe.net
Lorna Brown © 2026
page 17

10.2.5 Sequences with surds

Challenging · Mastery
Name:

Challenging

143
Find un and u20 for √2, √8, √18, …
144
A geometric sequence has u1 = 3 and u2 = 3√2. Find r, u3 and u5
145
An arithmetic sequence has u1 = 2√3 and d = √3. Find un and show that u8 = √243
146
Find and describe the mistake. Maya says √3, √12, √27 is geometric with r = √4 = 2, because 12 ÷ 3 = 4
147
Show that the ratio of 4, 2√2, 2, … is √22
Challenging score / 15

Mastery

148
Explain why simplifying each surd first makes it easier to tell whether a sequence is arithmetic
149
a) Write the first three terms of an arithmetic sequence with u1 = √2 and d = 3√2 b) Write un
150
A geometric sequence has u2 = 6 and u4 = 12 with r positive. Find r and u1 in simplest form
151
√2, √6, √18, … Show it is geometric, then find u10 in simplest form
Mastery score / 15
Parent / guardian signature:
MYP 4 · Year 10 · Unit 10.2 Exponents and Indices · Practice Bookletmathscafe.net
Lorna Brown © 2026
page 18

Homework and checking record

Hand this page in with your sheets
Name:

Your teacher will tell you which sheet and questions to do. Choose your level, set out your work in pen or pencil, then check it with the answers at the back using a green pen: circle wrong question numbers, and star ★ any you still cannot solve.

SheetQuestionsWhich ones I didChecked in green ✓Teacher
10.2.1 Index lawsQ1–20
10.2.1b Negative and fractional indicesQ21–38
10.2.2 Comparing exponentsQ39–57
10.2.3 Algebraic exponentsQ58–76
10.2.4 (a) Surds: what they are and simplifyingQ77–95
10.2.4 (b) Multiplying and collecting surdsQ96–114
10.2.4b Rationalising the denominatorQ115–132
10.2.5 Sequences with surdsQ133–151

Error analysis

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MYP 4 · Year 10 · Unit 10.2 Exponents and Indices · Practice Bookletmathscafe.net
Lorna Brown © 2026
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10.2.1 Index laws

Learning
1242a) (2 × 2 × 2) × (2 × 2) b) Five 2s, so 25 = 32334+5 = 39478−3 = 755(52)3 = 52 × 52 × 52 = 566a) 1 b) 1 c) 1. Any number to the power 0 is 1
Practising
7a) x7 b) y7 c) a15824 × x12 = 16x12912 ÷ 3 = 4 and x5−2 = x3, so 4x3103 × 4 = 12, a2 × a = a3, b × b3 = b4, so 12a3b41133 × (a2)3 × b3 = 27a6b3
Challenging
12(2x3)2 = 4x6, so the top is 12x10. Then 12x10 ÷ 6x5 = 2x5131 + 1 + 5 × 1 = 7. The index 0 only applies to the x in 5x014a) n − 4 = 6, so n = 10 b) 2n = 12, so n = 615The law only works when the bases are the same, and the indices are added only for the same base. 23 × 32 = 8 × 9 = 72 (but 65 = 7776)1629, or (23)3 = 29. Both are 512
Mastery
1753 ÷ 53 = 53−3 = 50. But any number divided by itself is 1, so 50 = 118Multiplying adds the indices: 34 × 32 = 81 × 9 = 729 = 36. Adding the values gives 81 + 9 = 90, which is not 729. There is no law for adding powers19Both are 212. The index is m × n, and m × n = n × m20Area = (25)2 = 210 = 1024 cm2

10.2.1b Negative and fractional indices

Learning
21Each step down divides by 2, so 2−1 = 12 and 2−2 = 1422a) 123 = 18 b) 1100 c) 1523a) The square root of 25 is 5 b) 10 c) The cube root of 8 is 2 d) 324a) 14 b) 32
Practising
25a) 19 b) 164 c) 110 00026Flip the fraction, then use the positive index. a) 24 = 16 b) (32)2 = 9427a) 2 b) 2 c) 1028Root first, then power. a) 22 = 4 b) 32 = 9 c) 23 = 8293−2+5 = 33 = 27
Challenging
30a) 13 b) 132 = 19 c) 123 = 1831Flip the fraction to make the index positive: (94)32. The square root of 94 is 32, and cubed it is 27832x−2+5−(−1) = x433A negative index means reciprocal, it does not make the number negative. 2−3 = 123 = 1834a) 2−5 b) 23 × 2−5 = 2−2 = 14
Mastery
35Add the indices: 12 + 12 = 1, so a12 × a12 = a1 = a. The number that multiplies by itself to give a is the square root of a36The denominator is the root and the numerator is the power. Square root of 4 is 2, then 23 = 837Negative index: take the reciprocal. Denominator 3: the cube root of 8 is 2. Numerator 2: 22 = 4. So 8−23 = 1438The values are 12, 2, 1 and 13. In order: 27−13, 2−1, 80, 412

10.2.2 Comparing exponents

Learning
398 = 23, so 2x = 23 and x = 340a) x = 2 b) x = 4 c) x = 341a) 22 b) 24 c) 254264 = 26, so x = 6431 = 50, so x = 0
Practising
44a) x = 8 b) x = 4 c) x = 64525 = 52 and 125 = 53, so 52x = 53, 2x = 3 and x = 3246116 = 4−2, so x = −2478 = 23, 16 = 24, so 3x = 4 and x = 43489 = 32, 27 = 33, so 2x = 3 and x = 32
Challenging
49a) 33x = 32, x = 23 b) 3x = 3−4, x = −4 c) 23x = 2−2, x = −23504 = 22, 32 = 25, so 2x = 5 and x = 525112 = 2−1, so 2−x = 23, −x = 3 and x = −352She forgot that 9 = 32, so 9x = 32x. Then 32x = 33, 2x = 3 and x = 32530.25 = 14 = 2−2, so x = −2
Mastery
545 is not a whole-number power of 3. 31 = 3 and 32 = 9, so x is between 1 and 2551 to any power is 1, so every value of x works. Comparing exponents needs a base that gives a different value for each exponent56a) 2x = 1024 = 210, so 10 hours b) 3x = 729 = 36, so 6 hours57x = 34 and y = 43, so x × y = 1. The exponents are reciprocals because one equation is the other turned round

10.2.3 Algebraic exponents

Learning
588 = 2359a) 27 b) 2660a) (22)x = 22x b) 23x c) 24x61The bases match, so x + 1 = 5 and x = 4622x = 8, so x = 4
Practising
639x = 32x, so 2x = x + 4 and x = 46425x = 52x, so x + 1 = 2x and x = 1654x+1 = 22(x+1) = 22x+2, so x − 1 = 2x + 2 and x = −36627x−1 = 33(x−1) = 33x−3, so 2x + 1 = 3x − 3 and x = 46725x−3 = 52x−6, so x + 2 = 2x − 6 and x = 8
Challenging
684x+2 = 22x+4, so 3x − 1 = 2x + 4 and x = 56922x+2 = 23x, so 2x + 2 = 3x and x = 2702−x = 22x+6, so −x = 2x + 6 and x = −271The 2 from 4 = 22 must multiply the whole exponent: 4x+1 = 22(x+1) = 22x+2. Then 2x + 2 = x + 5 and x = 372Left side: 44 = 256. Right side: 28 = 256. They are equal, so x = 3 works
Mastery
732x × 22x+2 = 23x+2. 128 = 27, so 3x + 2 = 7 and x = 537427 = 33, so 27x−1 = (33)x−1 = 33(x−1). The 3 multiplies the whole exponent x − 1, which gives 3x − 375a) 2t = 32, so t = 5 b) 2t = 22t−4, so t = 2t − 4 and t = 476For example 3x+2 = 9x. Solve: x + 2 = 2x, so x = 2. Check: 34 = 81 and 92 = 81

10.2.4 (a) Surds: what they are and simplifying

Learning
771, 4, 9, 16, 25, 36, 49, 64, 81, 10078√7 and √10. √16 = 4 and √25 = 5 are whole numbers, so they are not surds79√9 = 3, so √18 = 3√2802√281√12 = √4 × √3 = 2√3
Practising
82√16 × √3 = 4√383√25 × √3 = 5√384√36 × √2 = 6√285√9 × √5 = 3√5865 × 2√2 = 10√2
Challenging
87a) √36 × √5 = 6√5 b) 3 × 5√2 = 15√2 c) √100 × √2 = 10√2886√2 = √36 × √2 = √7289You cannot add under the roots. √9 = 3 and √16 = 4, so the sum is 3 + 4 = 790√98 = 7√2 and √32 = 4√291√75 = 5√3, so the answer is √3
Mastery
92The value is right, because 2√18 = √4√18 = √72. It is not in simplest form: √18 = 3√2, so the answer is 6√2. We use the highest perfect square factor, 3693√8 = 2√2 and √18 = 3√294√2 is irrational: its decimal 1.41421356… never ends and never repeats, so any decimal we write is only an approximation95Side = √50 = √25 × √2 = 5√2 cm

10.2.4 (b) Multiplying and collecting surds

Learning
96√6975, because a square root times itself gives the number983 × 2 = 6 and √2 × √5 = √10, so 6√10996√3. They are like surds, so add the numbers in front1004√5
Practising
10112√12 = 12 × 2√3 = 24√31025√3 − √3 × √3 = 5√3 − 31033 + 3√2 + √2 + 2 = 5 + 4√21044√3 − 2√3 = 2√31052√2 + 5√2 = 7√2
Challenging
1069 + 3√2 + 3√2 + 2 = 11 + 6√210716 − 3 = 13. The middle terms cancel1085 − 4 = 1109He squared each term and left out the middle terms. (3 + √2)(3 + √2) = 9 + 6√2 + 2 = 11 + 6√21103√5 + 2√5 − √5 = 4√5
Mastery
111√3 + √2 ≈ 1.732 + 1.414 = 3.146, but √5 ≈ 2.236. Roots do not add under one root. √3 and √2 are unlike surds, so the sum cannot be simplified112(2 + √3)2 = 4 + 4√3 + 3 = 7 + 4√3 cm2113h2 = 12 + 6 = 18, so h = √18 = 3√2 cm114√4x = 2√x, so 3√x = 3√5, √x = √5 and x = 5

10.2.4b Rationalising the denominator

Learning
1157116√22. We multiplied by 1, so the value does not change but how it is written does117a) 3√3 × √3√3 = 3√33 = √3 b) 10√55 = 2√5118a) 3 − √2 b) 4 + √5 c) √7 − 1
Practising
119a) 2√3 b) 2√2 c) 3√5120Multiply by √3√3: 3√36 = √3212110√26 = 5√2312216 − 3 = 13, a whole number123Multiply by 3 − √23 − √2. The denominator is 9 − 2 = 7, so the answer is 15 − 5√27
Challenging
124√2 − 12 − 1 = √2 − 11252(3 + √5)9 − 5 = 3 + √521266(√7 − 1)7 − 1 = √7 − 1127He used the same sign. The conjugate is 2 − √3. Then 2 − √34 − 3 = 2 − √31284(√5 + 1)5 − 1 = √5 + 1
Mastery
129The conjugate over itself is a fraction equal to 1, and multiplying by 1 does not change the value. The value stays the same but is written differently, with a rational denominator130√5(√5 − √2)5 − 2 = 5 − √1031312 + √31 + 2 − √31 = 4, because each denominator becomes 4 − 3 = 1132Width = 63 + √3 = 6(3 − √3)9 − 3 = 3 − √3 cm

10.2.5 Sequences with surds

Learning
133a) 2√3 b) 3√31342√5, 3√5 and 4√51354√2. Each term adds √2136a) √3, 2√3, 3√3 b) d = √3137un = n√3
Practising
1382√2, 4√2, 6√2. d = 2√2 and un = 2n√2139r = √3, since 2√3 ÷ 2 = √3. The next term is 6√3 × √3 = 18140r = √5. u6 = (√5)5 = 25√5141d = 2√5. un = √5 + (n − 1) × 2√5 = (2n − 1)√5. u10 = 19√5142Each term is the last times √2, so it is geometric with r = √2
Challenging
143Simplified: √2, 2√2, 3√2. un = n√2, so u20 = 20√2144r = √2. u3 = 3 × 2 = 6. u5 = 3 × (√2)4 = 12145un = 2√3 + (n − 1)√3 = (n + 1)√3. u8 = 9√3 = √81 × √3 = √243146She only checked the first pair. √27 ÷ √12 = 3√3 ÷ 2√3 = 1.5, not 2. The terms simplify to √3, 2√3, 3√3, so it is arithmetic with d = √31472√2 ÷ 4 = √22, and 2 ÷ 2√2 = 1√2 = √22. Both give the same ratio
Mastery
148After simplifying, the terms are multiples of the same surd, so you can see the gaps. For example 2√3, 3√3, 4√3 has a constant gap √3149a) √2, 4√2, 7√2 b) un = √2 + (n − 1) × 3√2 = (3n − 2)√2150u4 = u2 × r2, so r2 = 2 and r = √2. u1 = 6√2 = 3√2151r = √3, since √6 ÷ √2 = √3. u10 = √2 × (√3)9 = √2 × 81√3 = 81√6

Revision slides as text (easy to translate)

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Slide 1: Exponents and Indices

Revision slides: everything you need for the test, one idea per slide.

Slide 2: Key vocabulary (1 of 3)

Index (power, exponent): the small number that says how many times to multiply the base, e.g. the 3 in 2³

Base: the number that is being multiplied by itself, e.g. the 2 in 2³

Negative index: an index that gives a reciprocal: 2⁻³ = 12³ = 18

Fractional index: an index that means a root: 813 is the cube root of 8

Reciprocal: 1 divided by a number: the reciprocal of 8 is 18

Slide 3: Key vocabulary (2 of 3)

Exponential equation: an equation with the unknown in the index, e.g. 2x = 32

Rational number: a number that can be written as a fraction of two integers

Irrational number: a number that cannot be written as a fraction, e.g. √2

Surd: an irrational root left in exact form, such as √2 or √12

Like surds: surds with the same root part, e.g. 3√2 and 5√2, which can be added or subtracted

Slide 4: Key vocabulary (3 of 3)

Numerator: the number or expression above the line in a fraction

Denominator: the number or expression below the line in a fraction

Rationalise the denominator: rewrite a fraction so that the denominator has no surd

Conjugate: the same two terms with the opposite sign between them: the conjugate of 3 + √2 is 3 − √2

Slide 5: Index laws (positive and zero indices)

am × an = am+n (same base: add the powers). am ÷ an = am−n.

(am)n = amn. (ab)n = anbn.

a⁰ = 1 because an ÷ an = a0 = 1.

Expand to see why: x³ × x² = (x·x·x)(x·x) = x⁵.

The laws need the same base: 2³ × 3² cannot be combined.

Slide 6: Negative and fractional indices

a−n = 1 ÷ an: a negative index is a reciprocal. 2−3 = 18.

(a/b)−n = (b/a)n: flip, then use the positive power.

a1n = ⁿ√a. 912 = 3, 2713 = 3.

am/n = (ⁿ√a)m. 823 = (³√8)² = 4.

The pattern 2³ = 8, 2² = 4, 2¹ = 2, 2⁰ = 1, 2−1 = 12 shows why.

Slide 7: Exponential equations

If ax = ay (same base, a > 0, a ≠ 1) then x = y.

Write both sides with the same base: 2x = 32 = 2⁵, so x = 5. 9x = 27 gives 32x = 3³ and x = 32.

Answers can be negative or fractional: 2x = 18 = 2−3 gives x = −3.

With an algebraic exponent: 4x+1 = 2x+7 → 22x+2 = 2x+7 → 2x + 2 = x + 7 → x = 5. Check by substituting.

The rule fails for base 1 and 0.

Slide 8: Surds

A surd is an irrational root left exact, such as √2 or √12.

Simplify using the largest square factor: √12 = √4 × √3 = 2√3. √50 = 5√2.

Add/subtract like surds only: 3√2 + 5√2 = 8√2. √2 + √3 stays as it is.

Multiply: √a × √b = √(ab), and √a × √a = a. 2√3 × 3√2 = 6√6.

Expand brackets as normal: √2(3 + √2) = 3√2 + 2. (1 + √3)² = 1 + 2√3 + 3 = 4 + 2√3.

Slide 9: Rationalising the denominator

Rationalise = remove the surd from the denominator, because a rational denominator is easier to use and compare.

Single surd: 1/√2 = 1 × √2√2 × √2 = √22. Multiplying by √2/√2 is multiplying by 1, so the value is unchanged.

Conjugate: the same terms with the opposite sign. The conjugate of 3 + √2 is 3 − √2.

13 + √2 = (3 − √2)/((3 + √2)(3 − √2)) = 3 − √29 − 2 = 3 − √27.

The product of a number and its conjugate is rational: (a + √b)(a − √b) = a² − b.

Slide 10: Sequences with surd terms

Simplify every surd term first: √2, √8, √18 = √2, 2√2, 3√2.

That is an arithmetic sequence with d = √2.

Geometric check: √2, 2, 2√2 has r = √2 (2 ÷ √2 = √2, and 2√2 ÷ 2 = √2).

Write un in exact form: un = √2 × n for the first sequence.

Slide 11: Common mistakes

✕ “x³ × x² = x⁶.”

✓ Add the powers: x⁵.

✕ “2−3 = −8.”

✓ A negative index gives a reciprocal: 18.

✕ “813 = 83.”

✓ A power of 13 is a cube root: 2.

✕ “√2 + √3 = √5.”

✓ Unlike surds cannot be added: √2 + √3 stays as it is.

Slide 12: Common mistakes (continued)

✕ “(a + b)2 = a² + b².”

✓ Expand: a² + 2ab + b². So (1 + √3)² = 4 + 2√3.