10.1 Sequences
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The big idea. How can we be sure a pattern will keep working? Represent sequences, find general rules for arithmetic, geometric and quadratic sequences, and use recursive definitions.
Representing a sequence
- Show a sequence four ways: a picture, a table of terms, a graph (points, not a joined line) and an algebraic rule.
- The term number n and the term un: u1 is the first term.
- Triangle numbers: 1, 3, 6, 10, 15 ... rule un = n(n + 1) ÷ 2. The graph curves upwards.
- A straight-line graph means a constant difference (arithmetic); a curve means something else.
Shifting a known pattern
- Name the base sequence: squares (1, 4, 9, 16), cubes (1, 8, 27, 64), triangle numbers, powers of 2.
- Find the constant shift: 0, 3, 8, 15, 24 is one less than the squares, so un = n² − 1.
- Check with a term you did not use: u6 = 36 − 1 = 35.
Quadratic sequences (second differences)
- Build a difference table. If the first differences are not constant but the second differences are, the rule is quadratic: un = an² + bn + c.
- a = second difference ÷ 2. Subtract an² from each term to leave a linear sequence bn + c.
- Example 4, 9, 16, 25 ... first differences 5, 7, 9; second differences 2, 2, so a = 1; un = n² + 2n + 1.
- Check the rule with a term you did not use.
Arithmetic sequences
- Constant common difference d: 5, 8, 11, 14 has d = 3.
- un = u1 + (n − 1)d. For 5, 8, 11: un = 5 + 3(n − 1) = 3n + 2.
- Find a given term: u20 = 5 + 19 × 3 = 62.
- Find which term equals a value: 3n + 2 = 50 gives n = 16.
Geometric sequences
- Constant common ratio r: 3, 6, 12, 24 has r = 2.
- un = u1 × rn−1. For 3, 6, 12: un = 3 × 2n−1.
- A negative r alternates the sign: 2, −6, 18, −54 has r = −3.
- u6 = 3 × 2⁵ = 96.
Working backwards and equal properties
- Given two terms, count the gap. If u3 = 11 and u7 = 27: 4 steps give 16, so d = 4; u1 = 11 − 8 = 3.
- Geometric: if u2 = 6 and u5 = 48, then r³ = 8, r = 2 and u1 = 3.
- Equal differences: if x, x + 4, 3x are arithmetic then (x + 4) − x = 3x − (x + 4), so 4 = 2x − 4 and x = 4.
- Equal ratios: if a, 6, 24 are geometric then 6 ÷ a = 24 ÷ 6 = 4, so a = 1.5.
- Test each solution by writing out the terms.
Recursive definitions
- A recursive definition gives the first term and a rule that uses the previous term.
- Arithmetic: u1 = 5, un+1 = un + 3. Geometric: u1 = 3, un+1 = 2un.
- The explicit rule gives any term directly: un = 3n + 2. Convert between them.
- Always state the starting value and use the precise words.
Common mistakes
- ✕ “Join the points of a sequence graph with a line.” ✓ Only whole-number terms exist, so plot separate points.
- ✕ “un = u1 + nd.” ✓ The first term has no difference added: un = u1 + (n − 1)d.
- ✕ “Geometric rule: un = u1 × rn.” ✓ The power is n − 1: un = u1 × rn−1.
- ✕ “a in an² + bn + c is the second difference.” ✓ a is half the second difference.
- ✕ “A recursive rule alone is complete.” ✓ You must also state the starting value.
Practice booklet
Lorna Brown © 2026
Practice Booklet
- 10.1.1
- Representing sequences · Questions 1–15
- 10.1.2
- Shifted sequences · Questions 16–30
- 10.1.2b
- Second differences · Questions 31–45
- 10.1.3
- Arithmetic sequences · Questions 46–60
- 10.1.4
- Geometric sequences · Questions 61–75
- 10.1.5
- Working backwards · Questions 76–90
- 10.1.6
- Equal differences and equal ratios · Questions 91–105
- 10.1.7
- Recursive rules · Questions 106–120
- Homework
- Homework page and checking record
- Answers
- For checking and correcting in green pen
How to use this booklet and your homework
Read this firstChoosing your level
Every part of the unit has four levels. Start where you feel comfortable and move between them freely. Most questions ask you to explain as well as answer, because being able to say why is what makes a method stick.
Learning
Small numbers, with counters or a diagram beside you.
Practising
The standard question, with your reasoning written out.
Challenging
Working backwards, and finding what is wrong with someone else's thinking.
Mastery
Explaining why a rule must be true, and testing it on new cases.
Working on your homework
Pens and setting out
- Answers in blue or black non-erasable pen, or in pencil.
- Colour and highlighters are for annotating your work and showing the steps of a method.
- Never erase a mistake. Rework it underneath so you can see what changed.
- Got it wrong? Circle the question number, then make your correction and write your error analysis in green pen.
- Still can’t work out how to solve it? Put a star ★ next to the question number, so we know to go over it in class.
Each sheet
- Your name goes on every sheet, because they are handed in one at a time.
- Each question is worth up to 3 marks. If a question has parts (a, b, c…), each part is marked out of 3. At the end of each level, write your score out of the total for that level.
- Questions are numbered 1, 2, 3… all the way through the booklet, so we can say exactly which ones to do.
- If you are stuck after trying, ask for help. Showing me what you tried is a good start.
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10.1.1 Representing sequences
LearningKey vocabulary
| Word | Meaning | Example |
|---|---|---|
| sequence | a list of numbers that follows a pattern | 1, 3, 6, 10, … |
| term | one number in the sequence | the 3rd term is 6 |
| term number, n | the position of a term in the list | n = 4 is the 4th term |
| un | the term in position n | u4 = 10 |
| rule | a formula that gives any term from its term number | un = n(n + 1) ÷ 2 |
One sequence can be shown four ways: a picture, a table, a graph and a rule.
Learning
a) Work out the gaps between the terms.
b) Write the next two terms.
a) Write the sequence.
b) Do the points lie on a straight line? Explain.
c) Write the rule un = ____
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10.1.1 Representing sequences
PractisingPractising
a) u8
b) u10
a) Complete the table.
b) Do the points lie on a straight line? Explain.
a) Find the gaps.
b) Will the graph be a straight line or a curve? Explain.
c) Write a rule for un.
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10.1.1 Representing sequences
Challenging · MasteryChallenging
Mastery
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10.1.2 Shifted sequences
LearningName it, shift it, check it
| Step | What you do | Example: 2, 5, 10, 17, 26 |
|---|---|---|
| Name it | Which known sequence is it close to? Squares or cubes | 1, 4, 9, 16, 25 |
| Shift it | Subtract. What constant is added or taken away every time? | always + 1 |
| Check it | Substitute a term you did not use | n = 5: 25 + 1 = 26 |
Squares: 1, 4, 9, 16, 25. Cubes: 1, 8, 27, 64, 125.
Learning
a) What is added to each square to give the term?
b) Complete the rule un = n2 ____
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10.1.2 Shifted sequences
PractisingPractising
a) 5, 8, 13, 20, 29
b) −1, 2, 7, 14, 23
a) 0, 7, 26, 63, 124
b) 2, 9, 28, 65, 126 (compare with the cubes)
a) Find u8.
b) Which term equals 97?
c) Is 45 a term? Explain.
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10.1.2 Shifted sequences
Challenging · MasteryChallenging
Mastery
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10.1.2b Second differences
LearningKey vocabulary
| Word | Meaning | Example: 2, 6, 12, 20, 30 |
|---|---|---|
| first difference | the gap between one term and the next | 4, 6, 8, 10 |
| second difference | the gap between one first difference and the next | 2, 2, 2 |
| quadratic sequence | a sequence whose second differences are constant | rule an2 + bn + c |
a is half of the second difference. Then b = (first gap) − 3a, and c = u1 − a − b.
Learning
a) second difference 2
b) second difference 6
c) second difference 10
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10.1.2b Second differences
PractisingPractising
a) 6, 9, 14, 21
b) 2, 7, 14, 23
a) Find u10.
b) Which term equals 20? Try values of n.
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10.1.2b Second differences
Challenging · MasteryChallenging
Mastery
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10.1.3 Arithmetic sequences
LearningKey vocabulary
| Word | Meaning | Example: 4, 9, 14, 19 |
|---|---|---|
| arithmetic sequence | the same amount is added every time | + 5 each time |
| common difference, d | the amount added (negative if the terms fall) | d = 5 |
| u1 | the first term | u1 = 4 |
| rule | un = u1 + (n − 1)d | 4 + (n − 1) × 5 = 5n − 1 |
Learning
a) 4, 9, 14, 19
b) 50, 42, 34, 26
a) u1
b) d
c) u10
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10.1.3 Arithmetic sequences
PractisingPractising
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10.1.3 Arithmetic sequences
Challenging · MasteryChallenging
Mastery
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10.1.4 Geometric sequences
LearningKey vocabulary
| Word | Meaning | Example: 3, 6, 12, 24 |
|---|---|---|
| geometric sequence | each term is multiplied by the same number | × 2 each time |
| common ratio, r | the multiplier (divide a term by the one before) | r = 2 |
| rule | un = u1 × rn − 1 | 3 × 2n − 1 |
Learning
a) 2, 6, 18, 54
b) 400, 200, 100, 50
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10.1.4 Geometric sequences
PractisingPractising
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10.1.4 Geometric sequences
Challenging · MasteryChallenging
Mastery
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10.1.5 Working backwards
Learning · PractisingWorking backwards
| Sequence | Jump between two terms | Example |
|---|---|---|
| arithmetic | from ua to ub there are (b − a) jumps, so d = (difference of terms) ÷ (b − a) | u3 = 8, u6 = 23: d = 15 ÷ 3 = 5 |
| geometric | rb − a = ub ÷ ua, then take the root | u2 = 6, u5 = 162: r3 = 27 |
Learning
Practising
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10.1.5 Working backwards
Challenging · MasteryChallenging
Mastery
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10.1.6 Equal differences and equal ratios
LearningThe two properties
| Three consecutive terms a, b, c | What is equal | So |
|---|---|---|
| arithmetic | b − a = c − b (equal differences) | b is the mean of a and c |
| geometric | b ÷ a = c ÷ b (equal ratios) | b2 = ac |
Learning
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10.1.6 Equal differences and equal ratios
PractisingPractising
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10.1.6 Equal differences and equal ratios
Challenging · MasteryChallenging
Mastery
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10.1.7 Recursive rules
LearningKey vocabulary
| Word | Meaning | Example |
|---|---|---|
| recursive rule | gives the first term and how to get each term from the one before | u1 = 5, un+1 = un + 3 |
| explicit rule | gives any term straight from n | un = 3n + 2 |
Arithmetic: un+1 = un + d. Geometric: un+1 = r × un. Always state u1.
Learning
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10.1.7 Recursive rules
PractisingPractising
a) un = 8 − 2n
b) un = 3 × 2n − 1
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10.1.7 Recursive rules
Challenging · MasteryChallenging
Mastery
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Homework and checking record
Hand this page in with your sheetsYour teacher will tell you which sheet and questions to do. Choose your level, set out your work in pen or pencil, then check it with the answers at the back using a green pen: circle wrong question numbers, and star ★ any you still cannot solve.
| Sheet | Questions | Which ones I did | Checked in green ✓ | Teacher |
|---|---|---|---|---|
| 10.1.1 Representing sequences | Q1–15 | |||
| 10.1.2 Shifted sequences | Q16–30 | |||
| 10.1.2b Second differences | Q31–45 | |||
| 10.1.3 Arithmetic sequences | Q46–60 | |||
| 10.1.4 Geometric sequences | Q61–75 | |||
| 10.1.5 Working backwards | Q76–90 | |||
| 10.1.6 Equal differences and equal ratios | Q91–105 | |||
| 10.1.7 Recursive rules | Q106–120 |
Error analysis
Circle the number of any question you got wrong. Star ★ it if you still cannot solve it after correcting. Then write the questions you need to rework, and what you will do differently:
One thing I understand better now
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Answers
Check in green pen10.1.1 Representing sequences
10.1.2 Shifted sequences
10.1.2b Second differences
10.1.3 Arithmetic sequences
10.1.4 Geometric sequences
10.1.5 Working backwards
10.1.6 Equal differences and equal ratios
10.1.7 Recursive rules
Revision slides as text (easy to translate)
This is a plain-text version of the revision slides. Your browser can translate it into any language.
Slide 1: Sequences
Revision slides: everything you need for the test, one idea per slide.
Slide 2: Representing a sequence
Show a sequence four ways: a picture, a table of terms, a graph (points, not a joined line) and an algebraic rule.
The term number n and the term un: u1 is the first term.
Triangle numbers: 1, 3, 6, 10, 15 ... rule un = n(n + 1) ÷ 2. The graph curves upwards.
A straight-line graph means a constant difference (arithmetic); a curve means something else.
Slide 3: Shifting a known pattern
Name the base sequence: squares (1, 4, 9, 16), cubes (1, 8, 27, 64), triangle numbers, powers of 2.
Find the constant shift: 0, 3, 8, 15, 24 is one less than the squares, so un = n² − 1.
Check with a term you did not use: u6 = 36 − 1 = 35.
Slide 4: Quadratic sequences (second differences)
Build a difference table. If the first differences are not constant but the second differences are, the rule is quadratic: un = an² + bn + c.
a = second difference ÷ 2. Subtract an² from each term to leave a linear sequence bn + c.
Example 4, 9, 16, 25 ... first differences 5, 7, 9; second differences 2, 2, so a = 1; un = n² + 2n + 1.
Check the rule with a term you did not use.
Slide 5: Arithmetic sequences
Constant common difference d: 5, 8, 11, 14 has d = 3.
un = u1 + (n − 1)d. For 5, 8, 11: un = 5 + 3(n − 1) = 3n + 2.
Find a given term: u20 = 5 + 19 × 3 = 62.
Find which term equals a value: 3n + 2 = 50 gives n = 16.
Slide 6: Geometric sequences
Constant common ratio r: 3, 6, 12, 24 has r = 2.
un = u1 × rn−1. For 3, 6, 12: un = 3 × 2n−1.
A negative r alternates the sign: 2, −6, 18, −54 has r = −3.
u6 = 3 × 2⁵ = 96.
Slide 7: Working backwards and equal properties
Given two terms, count the gap. If u3 = 11 and u7 = 27: 4 steps give 16, so d = 4; u1 = 11 − 8 = 3.
Geometric: if u2 = 6 and u5 = 48, then r³ = 8, r = 2 and u1 = 3.
Equal differences: if x, x + 4, 3x are arithmetic then (x + 4) − x = 3x − (x + 4), so 4 = 2x − 4 and x = 4.
Equal ratios: if a, 6, 24 are geometric then 6 ÷ a = 24 ÷ 6 = 4, so a = 1.5.
Test each solution by writing out the terms.
Slide 8: Recursive definitions
A recursive definition gives the first term and a rule that uses the previous term.
Arithmetic: u1 = 5, un+1 = un + 3. Geometric: u1 = 3, un+1 = 2un.
The explicit rule gives any term directly: un = 3n + 2. Convert between them.
Always state the starting value and use the precise words.
Slide 9: Don’t fall for these
✕ Wrong: Join the points of a sequence graph with a line.
✓ Correct: Only whole-number terms exist, so plot separate points.
✕ Wrong: un = u1 + nd.
✓ Correct: The first term has no difference added: un = u1 + (n − 1)d.
✕ Wrong: Geometric rule: un = u1 × rn.
✓ Correct: The power is n − 1: un = u1 × rn−1.
✕ Wrong: a in an² + bn + c is the second difference.
✓ Correct: a is half the second difference.
✕ Wrong: A recursive rule alone is complete.
✓ Correct: You must also state the starting value.
Slide 10: Test yourself
1. Which is the rule for the triangle numbers 1, 3, 6, 10?
Answer: n(n + 1) ÷ 2. n = 4 gives 4 × 5 ÷ 2 = 10.
2. The sequence 0, 3, 8, 15, 24 has the rule...
Answer: n² − 1. It is one less than the square numbers.
3. An arithmetic sequence has u3 = 11 and u7 = 27. What is d?
Answer: 4. Four steps add 16, so d = 4.
4. With u3 = 11 and d = 4, what is u1?
Answer: 3. 11 − 2 × 4 = 3.









